解不等式x平方减8x加15分之x大于等于2

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2025-05-12 12:22:43
推荐回答(2个)
回答(1):

x/(x�0�5-8x+15)≥2x/(x�0�5-8x+15)-2≥0[x-2(x�0�5-8x+15)]/(x�0�5-8x+15)≥0(-2x�0�5+17x-15)/(x�0�5-8x+15)≥0(2x�0�5-17x+15)/(x�0�5-8x+15)≤0[(2x-15)(x-1)]/(x-3)(x-5)≤0所以需要满足x≤1或3

回答(2):

通分的[x-2(x-3)(x-5)]/[(x-3)(x-5)]≧0当x>3且x≠5解得3<x<6.x≠5