x/(x^2-8x+15)-2>0(x-2x^2+16x-30)/(x^2-8x+15)>0所以(-2x^2+17x-30)(x^2-8x+15)>0(2x^2-17x+30)(x^2-8x+15)<0(x-6)(2x-5)(x-3)(x-5)<04个零点是5/2,3,5,6此处是小于所以5
