(x²-x-1)/(x²+x+1)≥0 解此不等式解析：∵(x²-x-1)/(x²+x+1)≥0x²+x+1>0==>x∈R∴x²-x-1>=0解得x<=(1-√5)/2或x>=(1+√5)/2取二者交∴原不等式的解集为x<=(1-√5)/2或x>=(1+√5)/2
