把下列各式因式分解:(1)x 2 +x+ 1 4 ;(2)8a-4a 2 -4;(3)(a 2 +9) 2 -36a 2 :(4

2025-05-17 18:10:47
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回答(1):

(1)原式=(x+
1
2
2

(2)原式=-4(a 2 -2a+1)
=-4(a-1) 2

(3)原式=(a 2 +9+6a)(a 2 +9-6a)
=(a+3) 2 (a-3) 2

(4)原式=(a-b) 2 -c 2
=(a-b+c)(a-b+c);

(5)原式=(4x-9) 2

(6)原式=[(3(a-b)+2(a+b)] 2
=(5a-b) 2