对于有多个绝对值的不等式，要分段解｜x+2｜+|x|<=4 当x<=-2时 -(x+2)+(-x)<=4 -2x<=6 X>=-3且x<=-2 所以-3<=x<=-2当-2当x>0时 x+2+x<=4 2x<=2 x<=1且x>0 所以0把以上三式取并 则-3<=x<=1
