已知x-y=3,x2+y2=13,求x3y-8x2y2+xy3的值

2025-05-21 06:36:05
推荐回答(1个)
回答(1):

由已知得

(x-y)²=9

即x²+y²-2xy=9

所以,13-2xy=9

xy=2


x³y-8x²y²+xy³

=xy(x²-2xy+y²)-6x²y²

=xy(x-y)²-6(xy)²

=2×3²-6×2²

= - 6