如图,在平面直角坐标系中,△ABC的顶点A(1,3),B(1,O),C(3,0).(1)将△ABC平移得到△A1B1C1

2025-05-13 01:00:12
推荐回答(1个)
回答(1):

(1)


(2)出A2、B2、C2的坐标分别是:(0,-2),(3,-2),(3,0);

(3)作AD⊥x轴,延长CB交y轴于点E.
则S梯形ADEC=

1
2
(AD+CE)?DE=
1
2
(1+3)×3=6,
S△ECA2=
1
2
?EC?EA2=
1
2
×3×3=4.5,
S△ADA2=
1
2
AD?D2=
1
2
×1×6=3,
S△ACA2=S梯形ADEC+S△ECA2-S△ADA2=6+4.5-3=7.5.