(1)①原式= 1 4 a2-25b2;②原式=-3y3+2xy2+4;(2)原式= (x+1)(x?1) (x?1)2 + x(x?2) x?2 × 1 x = x+1 x?1 +1= 2x x?1 ,∵4x2=1,∴x=± 1 2 ,当x= 1 2 时,原式= 2× 1 2 1 2 ?1 =-2;当x=- 1 2 时,原式= 2×(? 1 2 ) ? 1 2 ?1 = 2 3 .