已知代数式M=x2+2y2+z2-2xy-8y+2z+17.(1)若代数式M的值为零,求此时x,y,z的值;(2)若x,y,z满足

2025-05-13 00:59:40
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回答(1):

(1)∵x2+2y2+z2-2xy-8y+2z+17=0,
∴(x-y)2+(y-4)2+(z+1)2=0,
∵(x-y)2≥0,(y-4)2≥0,(z+1)2≥0,
∴(x-y)2=0,(y-4)2=0,(z+1)2=0,
∴x-y=0,y-4=0,z+1=0,
∴x=y=4,z=-1,

(2)x=2,y=3,z=0.