已知各项均为正数的数列{a n }满足: a 1 =3, a n+1 + a n n+1 = 8 a n+

2025-05-14 10:00:04
推荐回答(1个)
回答(1):

(I)∵
a n+1 + a n
n+1
=
8
a n+1 - a n

∴a n+1 2 -a n 2 =8(n+1)
∴a n 2 =(a n 2 -a n-1 2 )+(a n-1 2 -a n-2 2 )+…+(a 2 2 -a 1 2 )+a 1 2 =8[n+(n-1)+…+2]+9=(2n+1) 2
∴a n =2n+1.…(5分)
(II)
b 2n
=
1
a 2n
=
1
(2n+1) 2
1
4n(n+1)
=
1
4
(
1
n
-
1
n+1
)
S n
1
4
[(1-
1
2
)+(
1
2
-
1
3
)+…+(
1
n
-
1
n+1
)]=
1
4
(1-
1
n+1
)<
1
4
…(12分)