余弦函数的导数是负的正弦数的详细证明方法是什么?

2025-05-22 22:09:50
推荐回答(1个)
回答(1):

cosx-cosy=-2sin[(x+y)/2]sin[(x-y)/2]

[cos(x+dx)-cosx]/dx = -2sin(x+dx/2)*sin(dx/2)/dx= -sin(x+dx/2) (sin(dx/2)/(dx/2))
dx->0
sin(dx/2)/(dx/2) ->1
sin(x+dx/2) -> sinx