求xye^(x^2+y^2)dy,详解!谢谢

2025-05-19 08:26:22
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回答(1):

ffD xye^(x^2+y^2)dxdy D={(x,y)|a<=x<=b,c<=y<=d}

ffD xye^(x^2+y^2)dxdy               D={(x,y)|a<=x<=b,c<=y<=d}D在ff的下方