20032003×200220022003-20022002×200320032004

20032003×200220022003-20022002×200320032004
2025-05-15 21:43:35
推荐回答(1个)
回答(1):

20032003×200220022003-20022002×200320032004
=20032003×(200220022002+1)-20022002×(200320032003+1)
=20032003×200220022002+20032003×1-20022002×200320032003-20022002×1
=(2003×10001)×(2002×100010001)+20032003-(2002×10001)×(2003×100010001)-20022002
=(2002×2003×10001×100010001)-(2002×2003×10001×100010001)+(20032003-20022002)
=0+10001
=10001