√(x²-2x+1)+√(x²-6x+9)=√(x-1)²+√(x-3)²=|x-1|+|x-3|x≥1 x-1≥0 |x-1|=x-1x≤3 x-3≤0 |x-3|=3-x√(x²-2x+1)+√(x²-6x+9)=|x-1|+|x-3|=x-1+3-x=2
