如图所示
ln(-x+√x²+1)+ln(x+√x²+1)=ln〔(-x+√x²+1)*(x+√x²+1)〕=ln〔(x²+1)-x²〕=ln1=0∴ln(-x+√x²+1)=-ln(x+√x²+1)满意请采纳噢～
