ZL=20+jwl=20+j2PIfL=20+518.1j=518.485-87.79，Z=300+518.1j=598.69-59.93
假设以电源电压为0度，I=U/Z=220*2^0.5/(598.69-59.93)=0.52-(-59.93)
UR=I*R=(0.52-(-59.93))*280=145.6-(-59.93)
UL=I*ZL=(0.52-(-59.93))*(518.485-87.79)=269.61-27.86
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