tan2a=tan(a+a)=2tana/1-tan^2a=24/7cos(a-b)>0 0<b<a<π/2 ∴a-b在第一象限sin(a-b)=√(1-cos^2(a-b))=5/13同理sina=3/5cos-(a-b)=cos(a-b)=cos(b-a)=12/13sin-(a-b)=-sin(a-b)=sin(b-a)=-5/13sinb=sin(b-a+a)=sin(b-a)cosa+cos(b-a)sina=16/65楼主有不懂的记得追问
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