(1)因为全集U={1,2,3,4,5,6,7,8,9,10},集合A={1,3,5,8,9},B={2,5,6,8,10},所以A∪B={1,2,3,5,6,8,9,10},CUA={2,4,6,7,10},CUB={1,3,4,7,9}.(CUA)∩(CUB)={2,4,6,7,10}∩{1,3,4,7,9}={4,7};(2)集合的“差”:A-B={x|x∈A,且x?B},所以集合A={1,3,5,8,9},B={2,5,6,8,10},集合A-B={1,3,9}.