JAVA题求解,完整答案,谢谢!!

2025-02-26 09:03:13
推荐回答(2个)
回答(1):

import java.util.Scanner;

public class MultiplyDemo {

    public static void main(String[] args) {
        multiply();
    }

    public static void multiply() {
        Scanner scan = new Scanner(System.in);
        double multiplied = 1;// 乘积
        boolean continueRun = true;// 程序是否继续进行
        try {
            do {
                if (multiplied > 100000) {// 乘积超过100000抛出异常信息
                    throw new Exception("乘积:" + multiplied + "错过100000");
                }
                double value = scan.nextDouble();
                multiplied = multiplied * value;
                
            } while (scan.hasNextDouble() && continueRun);

        } catch (Exception e) {// 处理异常信息
            continueRun = false;
            e.printStackTrace();
        }

    }
}

回答(2):

import java.util.Scanner;
public class MyException extends Exception {
public MyException(String msg) {
super(msg);
}

public static void multiply(int s) throws MyException {
if (s>10000) {
throw new MyException("乘积大于10000报错!");
}
System.out.println(s);
}

public static void main(String[] args) {
try{
Scanner sc=new Scanner(System.in);
System.out.println("请输入一个整数");
int i =sc.nextInt();
while(i<=10000){
System.out.println("请再次输入一个整数");
int j =sc.nextInt();
i*=j;
multiply(i);
System.out.println("两个数相乘="+i);
}

}catch(MyException e){
e.printStackTrace();
}
}
}