解：因为√3sin(x+π/12)+cos(x+π/12) =2×[(√3/2)×sin(x+π/12)+(1/2)×cos(x+π/12)] =2×[cos(π/6)sin(x+π/12)+sin(π/6)cos(x+π/12)] =2sin(x+π/6+π/12) =2sin(x+π/4)又因为√3sin(x+π/12)+cos(x+π/12)=2/3，所以2sin(x+π/4)=2/3，则sin(x+π/4)=1/3，又因为-π/2
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