∵∠1=∠BAC,∴∠ABE+∠BAE=∠BAE+∠EAC,∴∠ABE=∠EAC,∵∠1=∠2,∴∠AEB=∠CFA,又∵AB=AC,∴△ABE≌△CAF,∴S△ABE+S△CDF=S△ACD=2/3S△ABC=6 有疑问,请追问;若满意,请采纳,谢谢!