已知sinα=-3⼀5,α属于(3π⼀2,2π),求cos(π⼀4-α)的值

2025-04-10 12:51:10
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回答(1):

sinα=-3/5 (sinα)^2+(cosα)^2=1
α属于第四象限,cos=4/5 sin2α=2sinαcosα=-24/25

cos(π/4-α)
=cos(90-2α)/2
=+-根号{[1+cost(90-2α)]/2}
=根号[(1+sin2α)/2]
=(根号2)/10或-(根号2)/10