AD = AB + BC + CDAB = 2BMBC = 1CD = 2CNMN= BM+CN+ BC所以BM+CN = MN -BC = 6-1 =5所以AB+CD = 2(BM+CN)=10所以AD = 10 +1 =11
MN=MB+BC+CN=1/2AB+BC+1/2CD=BC+1/2(AB+CD)带入条件,可算出AB+CD长度,AD=AB+CD+BC,其中BC已知。
no