∫(x-2) /(x^2-x+1)dx=(1/2)∫(2x-1) /(x^2-x+1)dx-(3/2)∫1 /(x^2-x+1)dx=(1/2)ln(x^2-x+1)-(3/2)(2/√3)arctan((x-1/2)/(√3/2)+C=(1/2)ln(x^2-x+1)-√3arctan((2x-1)/√3)+C
