如图,当S1、S2闭合时,R2被短路,电路中只有R1,U=U1=9V,I=1.5A,R1= U1 I = 9V 1.5A =6Ω;当S1闭合、S2断开时,两电阻串联,U=9V,U1′=6V,U2=U-U1′=9V-6V=3V,∵I′= U′1 R1 = U2 R2 ,即: 6V 6Ω = 3V R2 ,∴R2=3Ω.故答案为:3.