解不等式x+1⼀x-2<=2

2024-12-15 04:02:42
推荐回答(3个)
回答(1):

x+1/x-2<=2
(x+1)/(x-2)-2≤0
(x+1-2x+4)/(x-2)≤0
(x-5)/(x-2)≥0
x≥5或x<2

回答(2):

(x+1)/(x-2)≤2
(x+1)/(x-2)-2(x-2)/(x-2)≤0
(x+1-2x+4)/(x-2)≤0
(-x+5)/(x-2)≤0
(x-5)(x-2)≥0
得 x≥5 或 x<2

回答(3):

5