1.算不出具体。答案小于4大于32体积变为原来的2倍,浓度变为原来一半。0.2mol/L变成0.1mol/L PH=1
1.根据[H+]=√Kacc=[H+]^2/Ka=0.001^2/1.75×10^-5=0.057mol/L稀释10倍后[H+]=√(1.75×10^-5×0.0057)=2.39×10^-4PH=-lg2.39×10^-4=3.622.0.2mol/L的盐酸,与等体积水混合,如果不考虑体积的变化,那么浓度是0.1mol/LPH=-lg0.1=1