高数正项级数审敛法计算求解!!

2025-05-11 19:21:52
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3) By nth root test, the limit = a. Therefore, at a < 1, it is convergent. At a > or = 1, it is divergent.
4) By limit comparison test, compare it to a convergent series {1/n^2}, the limit of ratio = 2. Therefore, it is convergent.