(2009?西城区二模)如图,在直三棱柱ABC-A1B1C1中,AB⊥BC,AB=BC=1,AA1=2,D是AA1的中点.(Ⅰ)求异

2025-05-06 15:46:43
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解:(Ⅰ)如图,以B为原点,BC、BA、BB1分别为x、y、z轴,建立空间直角坐标系O-xyz,
则B(0,0,0),C(1,0,0),A(0,1,0),
B1(0,0,2),C1(1,0,2),A1(0,1,2),D(0,1,1),

A1C1
=(1,?1,0) 
B1D
=(0,1,?1),
cos<
A1C1
 
B1D
>=
A1C1
?
B1D
|
A1C1
|?|