解：y＜√(x-1) + √(1-x) + 1/2 x-1≥0，即x≥11-x≥0，即x≤1∴x-1=0，x=1∴y＜√(x-1) + √(1-x) + 1/2 = 1/2∴1-y＞1/2∴|1-y|/(y-1) = (1-y)/(y-1) = -1
