一平面简谐波的波动方程为y=0.02cos2π(10t-x⼀5)(SI),t=0.25S时处于平衡位置,

2025-05-20 07:15:26
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回答(1):

分别把t,和x带进去就行了啊。第一个y(x)=10cos(16π-π/2-π/10*x)=10cos(-π/2-π/10*π)=-10sin(π/10*x)第二个y(t)=10cos(8πt-π/2-π/2)=10cos(8πt-π)=-10cos(8πt)