在数列{an}中,若a1=14,且log2an+1=1+log2an,则满足ai∈{1,2,3,4,…,100}的i的个数为(  )A.

2025-05-17 07:06:33
推荐回答(1个)
回答(1):

∵log2an+1=1+log2an=log2(2an),

an+1
an
=2,
a1
1
4

∴{an}是首项为
1
4
,公比为2的等比数列,
an
1
4
?2n?1
=2n-3
∵ai=2i-3∈{1,2,3,4,…,100},
∴i=3,4,5,6,7,8,9.
∴满足ai∈{1,2,3,4,…,100}的i的个数为7个.
故选B.