∵am=2，an=3，则a(2m+3n)=a2m×a3n=(am)2×(an)3=22×33=4×27=108
（b3）2+3b2×（b2）2
=b6+3b2×b4
= b6+3b2+4
= b6+3b6
= 4b6
a^(2m+3n)=a^2m*a^3n=(a^m)^2*(a^n)^3=2^2*3^3=4*27=108
