解:设甲乙两根绳子的长度分别为x,y米剩下的长度,甲:(1/4)x+(3/4)乙:y-(3/4)-(3/4)(y-3/4)=(1/4)(y-3/4)=(1/4)y-3/16(1/4)x+(3/4)=(1/4)y-(3/16)(1/4)(x-y)=(-3/4)-(3/16)x-y=-[(3/4)+(3/16)]/(1/4)x-y<0x<y∴乙的长