1、由题意知a=2,c= √3,所以b=1 所以标准方程为:x^2/4+y^2=1。2、设M(x,y),P(x1,y1) 于是有:x=(x1+1)/2; y=(y1+1/2)/2; x1=2x-1;y1=2y-1/2;因为P在椭圆上,于是有(2x-1)^2/4+(2y-1/2)^2=1;M的轨迹方程为:x平方+4y平方-2y-x-1/2=0.
(1)x^2/4 y^2=1 (2)(x-1/2)^2 (2y-1/2)^2=1