求定积分,如图

2025-05-19 07:54:09
推荐回答(2个)
回答(1):

回答(2):

∫(π->2π) x|sinx| dx
=-∫(π->2π) xsinx dx
=∫(π->2π) x dcosx
=[xcosx]|(π->2π) - ∫(π->2π) cosx dx
=2π +π - [sinx]|(π->2π)
=3π