用到连续函数的极限性质:y=f(u)在u=u0连续,limg(x)=u0则limf[g(x)]=f(u0)而 y=e^u在(-∞,+∞)内连续所以,只要limg(x)=A就有,lime^g(x)=e^A=e^[limg(x)]