求由方程式xy=e x+y所确定的隐函数y=y(x)的导数,x+y在右上方

2025-05-14 02:22:24
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回答(1):

先对方程两边求导,
y+xy'=e^(x+y)•(1+y')
=xy(1+y'),
xy'(1-y)=y(x-1),
y'=y(x-1)/[x(1-y)].