已知a>0,b>0且a+b=1,求证:(a+1⼀a)(b+1⼀b) 25⼀4

2025-05-13 15:28:53
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回答(1):

左式=ab+a/b+1/ab+b/a
=(a2b2+a2+1+b2)/ab
=[a2b2+(1-2ab)+1]/ab
=[(ab-1)2+1]/ab

a+b=1
ab≤[(a+b)/2]²=1/4

所以(ab-1)^2+1≥25/16,0相乘得到,左式≥25/4