编程题 求ax눀+bx+c=0方程的根。a、b、c由键盘输入,设b눀-4ac>=0

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2025-05-19 16:11:50
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回答(1):

#include
#include
void main()
{
double a;
double b;
double c;
double x1;
double x2;
cout<<"请输入系数a:"< cin>>a;
cout<<"请输入系数b:"< cin>>b;
cout<<"请输入系数c:"< cin>>c;
if(b*b<4*a*c)
{
cout<<"您输入的系数没有实数根,请重新输入!"< cout<<"请输入系数a:"< cin>>a;
cout<<"请输入系数b:"< cin>>b;
cout<<"请输入系数c:"< cin>>c; }
x1=(-b+sqrt(b*b-4*a*c))/(2*a);
x2=(-b-sqrt(b*b-4*a*c))/(2*a);
cout<<"x1="<