∫x/(1-x)³dx=-∫(1-x-1)/(1-x)³dx=-∫(1-x)/(1-x)³dx+∫1/(1-x)³dx=∫1/(1-x)²d(1-x)-∫1/(1-x)³d(1-x)=-1/(1-x)+1/2(1-x)²+C
