解:设小明原来有X个,则小亮原来有(1-1/4)X个X-1/6X=(1-1/4)X+1/6X-25/6X=3/4X+1/6X-25/6X=11/12X-211/12X-5/6X=21/12X=2X=2÷1/12X=24