在标准状况下,CH4气体2.24L,n(CH4)=
=
=0.1mol,CH
4+2O
2CO
2+2H
2O,消耗氧气n(O
2)=2n(CH
4)=0.2mol,同时生成水的物质的量n(H
2O)=2n(CH
4)=0.2mol,m(H
2O)=n(H
2O)×M=0.2mol×18g/mol=3.6g,
n(CO
2)=n(CH
4)=0.1mol,若将生成的CO
2气体用2mol?L
-1的NaOH溶液吸收,CO
2+2NaOH═Na
2CO
3+H
2O,n(NaOH)=cv=2n(CO
2)=0.2mol,v(NaOH)=
=
=0.1L,
答:消耗O
2物质的量为0.2mol;同时生成3.6克的水;需要NaOH溶液的体积为0.1L.