设公路全长x千米
(1/5)x+100+(2/7)[x-(1/5)x-100]=x-500
(1/5)x+100+(2/7)(4/5)x-200/7=x-500
(1/5)x+100+(8/35)x-200/7=x-500
7x+3500+8x-1000=35x-17500
15x+2500=35x-17500
20x=20000
x=1000米
设x
1/5x+100+2/7(x-1/5x-100)=x-500
x=1000
[500÷(1-2/7)+100]÷(1-1/5)
=600÷4/5
=750米
设全长x米
1/5x+100+(x-1/5x-100)x2/7+500=x
x=1000米
100%正确,请采纳!
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