python输入k个大于等于1小于等于10的正整数,计算1、5、10出现次数?

2025-05-21 01:46:15
推荐回答(2个)
回答(1):

def count_int(nums):

count = {1: 0, 5: 0, 10: 0}
for num in nums:
if num == 1 or num == 5 or num == 10:
count[num] = count[num] + 1
return count

回答(2):

集结号就你和临河里