因为 a1+a5=2a3,所以S5=5(a1+a5)/2=5a3=35,解得 a3=7设公差为d,则 a2=a3-d=7-d,a6=a3+3d=7+3d由a2,a3+1,a6成等比,得a2·a6=(a3+1)²,即 (7-d)(7+3d)=6449+14d-3d²=643d²-14d+15=0,解得 d=3或d=5/3所以 a1=a3-2d=1或 a1=11/3an=a1+(n-1)d=3n-2或an=5n/3 +2