当只闭合开关S1时,等效电路如图甲所示;
当只闭合开关S2时,等效电路如图乙所示;
当开关S1、S2、S3闭合时,等效电路如图丙所示.
(1)∵P=I2R,P3=4P3′,
∴由图甲、图乙得
=P3
P
=
R3
I
R3
I
=
I
I
,即4 1
=I1 I2
,2 1
∵U=IR,2U1=U2,
∴
=U1 U2
=
I1R1
I2R2
=2R1
R2
1 2
解得:
=R1 R2
;1 4
(2)∵电源两端电压不变,
∴由图甲、乙得:I1(R3+R1)=I2(R3+R2),
解得:R3=2R1,
∵P=I2R,P2=1.6W,
∴由图乙得P2=I22R2=(
)2R2=U
R2+R3
=1.6W,U2 9R1
∴
=14.4W; U2 R1
当开关S1、S2、S3闭合时,由丙图知电路消耗的功率为:
P=
+U2 R1
=U2 R2
=5U2
4R1
×14.4W=18W. 5 4
答:(1)电阻R1与电阻R2的比值为1:4;
(2)当开关S1、S2、S3都闭合时,电路消耗的电功率为18W.