大学高数下题目

如图
2025-05-19 12:49:59
推荐回答(1个)
回答(1):

z = [cos(6x+7y)]^2 ?z/?x = -2cos(6x+7y)sin(6x+7y)·6 = -6sin2(6x+7y) ?z/?y = -2cos(6x+7y)sin(6x+7y)·7 = -7sin2(6x+7y) dz = -6sin2(6x+7y)dx - 7sin2(6x+7y)dy = - sin2(6x+7y)(6dx+7dy)