2x^2-x<12x^2-x-1<0(2x+1)(x-1)<0令y=(2x+1)(x-1)=0解得x=-1/2或x=1当-1/2即2x^2-x<1
分解因式得：（2x+1）*（x-1）<0,分类讨论可得：-1/2
2x^2-x<1 2x^2-x-1<0(2x+1)(x-1)<0-1/2
