图中的实线是一列简谐波在某时刻的波形曲线,经 0.5s 后,其波形如图中虚线所示.( 1 )若周期T>0.5s.

2025-05-22 02:00:15
推荐回答(1个)
回答(1):

(1)由图读出波长λ=24m.若周期T>0.5s,波是向左传播的距离为x 1 =
3
4
λ,时间t 1 =
3
4
T
1 ,则T 1 =
2
3
s
,波速v 1 =
λ
T 1
=36m/s.
    (2)若周期T<0.5s,波是向右传播的距离x 2 =(n+
1
4
)λ=(24n+6)m,(n=1,2,…),波速v 2 =
x 2
t
=(48n+12)m/s,周期T 2 =
λ
v 2
=
4
4n+1
s,(n=1,2,…).
答:( 1 )若周期T>0.5s.波是向左传播的,波速是36m/s,波的周期是
2
3
s

    ( 2 )若周期T<0.5s,波是向右传播的,波速v 2 =(48n+12)m/s,周期T 2 =
4
4n+1
s,(n=1,2,…).